Week of 22 February 2010

Three weeks till Spring Break everyone!!! We can make it!

Here's what's going on this week (B WEEK):

Algebra 1
Monday - 2nd hour finish tests; 5th, 7th hours bonus work
Tuesday - 7.2 Exponential Equations
Wednesday - 7.2 assignment (p 378 1-3, 5, 6, 9; bonus 14)
Thursday/Friday - 7.6 Zero & Negative Exponents

Algebra 2
Monday - Finish up 7.5 Complex Numbers (p 394 1-7, 9-11, 13, 14; bonus 8) due 2/23
Tuesday - 7.6 Factoring Polynomials
Wednesday - 7.6 assignment (p 402 1-4, 6-8, 11-13; bonus 10) due 2/26
Thursday/Friday - Chapter 7 Review

There will be a Chapter 7 Test for Algebra 2 on MONDAY 1 MARCH 2010.

Week of 15 February 2010

Hey everyone - I apologize for not getting last week's schedule up! If you need any of the assignments, let me know in class or email me - mpatchin@hardingfinearts.org

This week, however, this is what we're looking at:

Algebra 1
Monday - Section 6.7 Systems of Inequalities with in-class assignment
Tuesday - Section 6.7 assignment (p 358 1-5, 7, 10, 11, 16; bonus 12) due 2/17
Wednesday - Chapter 6 Review
Thursday - Chapter 6 Review
Friday - Chapter 6 Test

Algebra 2
Monday - Section 7.4 Quadratic Formula with in-class assignment
Tuesday - Section 7.4 assignment (p 388 1-10, 14, 15; bonus 12) due 2/18
Wednesday - Begin Section 7.5 Complex Numbers
Thursday - Finish Section 7.5
Friday - Section 7.5 assignment (p 394 1-7, 9-11, 13, 14; bonus 8) due 2/22

Th-th-th-that's all folks! (are you guys too young to know where that's from?)
<3 Miss P

Algebra I Quiz Solutions

Some helpful information:
point-slope form: y = y1 + m(x - x1)
slope-intercept form: y = mx + b
slope formula: m = (y2 - y1)/(x2 - x1)

1) Use two points in the table to calculate the slope: (3, 12) and (7, 24). m = (24 - 12)/(7 - 3) = 12/4 = 3. Use any point to write the equation in point-slope form. (3, 12). y = 12 + 3(x - 3)

2) Use the points on the graph to count the slope. From the first to the second point (left to right), I count up 2, right 1, which gives me the slope 2/1 = 2. The y-intercept is at 2, so my equation in slope-intercept form is y = 2x + 2.

3) Same process as #2. The slope is counted down 3, right 2, which gives me a slope of -3/2 = -1.5. The y-intercept is 6, so my equation is y = -1.5x + 6.

4) Use the slope formula: m = (-4 - -1)/(9 - -4) = (-4 + 1)/(9+4) = -3/13

5) m = (-4 - 4)/(-4 - 3) = -8/-7 = 8/7

6) m = (0 - 0)/(1 - 0) = 0/1 = 0

Week of 1 February 2010

Welcome back from Winter Break Pt. 2!! Hope you guys enjoyed the break, because if we had to hurry before, we definitely need to hustle now!!

Here's what's on tap this week:

Algebra 1
Monday - NO SCHOOL
Tuesday - NO SCHOOL
Wednesday - Start Section 6.2 Solving Systems of Equations with Substitution
Thursday - Short quiz; Finish 6.2 and start the assignment p 320 (1-7, 9, 14; bonus 10) due 2/8/10
Friday - Start Section 6.3 Solving Systems of Equations with Elimination

Algebra 2
Monday - NO SCHOOL
Tuesday - NO SCHOOL
Wednesday - Start Section 7.2 Equivalent Quadratic Forms
Thursday - Finish Section 7.2 and start the assignment p 372 (1-5, 8, 9, 11, 13-16; bonus 12) due 2/8/10
Friday - Start Section 7.3 Completing the Square